The vertex at (-2, 3) and the focus at (1,3)
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Answered by
0
Answer:
The equation of parabola is
(
y
−
3
)
2
=
16
(
x
−
2
)
Explanation:
Focus is at
(
6
,
3
)
and vertex is at
(
2
,
3
)
;
h
=
2
,
k
=
3
.
Since focus is at right of vertex, parabola opens right ward
and
a
is positive. The equation of right opened parabola is
(
y
−
k
)
2
=
4
a
(
x
−
h
)
;
(
h
.
k
)
;
being vertex and focus is at
(
h
+
a
,
k
)
∴
2
+
a
=
6
∴
a
=
6
−
2
=
4
. Hence equation of
parabola is
(
y
−
3
)
2
=
4
⋅
4
(
x
−
2
)
or
(
y
−
3
)
2
=
16
(
x
−
2
)
graph{(y-3)^2=16(x-2) [-80, 80, -40, 40]} [Ans]
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