Question

the vertex of parabola y2+6x-2y+13=0 is ?​

Answer 1

Answer:

(-2,1)

Step-by-step explanation:

y^2-2y+1+6x+12=0

(y-1)^2=-6(x+2)

Compare with equation, (y-y1)^2=-4a(x-x1)

where (x1,y1) is vertex of parabola.

So, vertex of parabola=(-2,1)