Question

the vertex of y=-(x-2)(x-4) is

Answer 1

Answer:(3, 1)

Step-by-step explanation:

y = -(x-2)(x-4)

y = -x² + 6x - 8

using quadratic formula, we have

x = -b/2a

x = -b/2a ± sqrt(b²-4ac)/2a

x = -6/-2 ± sqrt(36 - 32)/-2

x = -6/-2 = 3

we know, vertex is (x, y) or (-b/2a, f(-b/2a))

y = f(x) = -x² + 6x - 8

y = f(3) = -3² +6(3) - 8

y = 1

vertex is (3,1)

check by graphing the given equation to check its correctness.

(my 100th answer and probably my last one)