the vertical angle of an isoceles triangle is100degree .find its base angle
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we know that in isosceles triangle base angle are equal so. the angle be x
x+x+100=180
2x=180-100
2x=80
x=40
x+x+100=180
2x=180-100
2x=80
x=40
adiRana1:
thank you so much sir
Answered by
1
Hello dear!!!
Here's your answer...
We know that, opposite angles of equal sides are equal.
So,one of the angle is 100.
Let,the other 2 angles be x
Sum of all angles in a triangle is 180°
x+x+100=180
2x+100=180
2x=180-100
2x=80
x=80/2
x=40°
Angles of an isosceles triangle are 40°,40°,100°
Hope this helps you
:) :) :) :) :-)
Here's your answer...
We know that, opposite angles of equal sides are equal.
So,one of the angle is 100.
Let,the other 2 angles be x
Sum of all angles in a triangle is 180°
x+x+100=180
2x+100=180
2x=180-100
2x=80
x=80/2
x=40°
Angles of an isosceles triangle are 40°,40°,100°
Hope this helps you
:) :) :) :) :-)
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