the Vertical angle of an isosceles triangle is 100 degree find its base angle
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ok lemme try
Let ΔABC be an isosceles triangle with vertical angle ∠A=100 ∘
and AB=AC.
Then,
AB=AC⇒∠B=∠C
But, ∠A+∠B+∠C=180 ∘
∴100 ∘
+2∠B=180 ∘
⇒∠B=40 ∘
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