Question

the vertical angle of an isosceles triangle is 100° . find its base angle.​

Answer 1

Answer:

40°

Step-by-step explanation:

A=100°

B=C (base angles are equal)

in triangle abc

A+B+C=180

100+C+C =180

2C=180-100

2C=80

C=40°

B=40°(B=C)

Answer 2

Let its base angles be x

As we know

base angles of isosceles triangle is equal.

Then as given

It's vertical angle = 100°

According to question

x + x + 100 = 180 ( angle sum property of triangle)

2x = 180-100

2x = 80

x = 80/2

x = 40

Thus the base angle of the isosceles triangle is 40°.

I hope this answer help you... Please make my answer brainliest... Thank you..