Math, asked by anoushka71987, 1 month ago

The vertical angle of an isosceles triangle is 15 degree more than each of its base angles. Find each angle of the triangle

Answers

Answered by pprathibha949
0

Answer:

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Step-by-step explanation:

Let each angle of the base of the isosceles triangle = x°

Then vertical angle = x + 15°

Now x + x + x + 15° = 180°

(Sum of angles of a triangle)

⇒ 3x + 15° = 180°

⇒ 3x = 180° - 15° = 165°

∴ x = 165°/3 = 55°

Hence each base angle = 55°

and vertical angle = 55° + 15° = 70°

Answered by nilanjandasviiif
0

Answer:

70⁰

Step-by-step explanation:

let each angle of the base of the isosceles triangle =X⁰

Then vertically angle = X+15⁰

Now x+x+x+15⁰=180⁰

(sum of angles of a triangle)

=3x +15⁰=180⁰

=3X=180⁰-15⁰ =165⁰

X=165⁰/3 =55⁰

Hence each base angles =55⁰

and vertical angle =55⁰+15⁰=70⁰(Ans)

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