Math, asked by ishiv465, 15 hours ago

The vertical angle of an isosceles triangle is 25° more than each of its base angles. Find each angle of the triangle. photo give ​

Answers

Answered by divyaoberoi
0

Answer:

70 °

Step-by-step explanation:

Let each angle of the base of the isosceles triangle = x°

Then vertical angle = x + 15°

Now x + x + x + 15° = 180°

(Sum of angles of a triangle)

⇒ 3x + 15° = 180°

⇒ 3x = 180° - 15° = 165°

∴ x = 165°/3 = 55°

Hence each base angle = 55°

and vertical angle = 55° + 15° = 70°

Answered by sohamandsnehal
0

Answer:

Let each angle of the base of the isosceles triangle = x°

Then vertical angle = x + 15°

Now x + x + x + 15° = 180°

(Sum of angles of a triangle)

⇒ 3x + 15° = 180°

⇒ 3x = 180° - 15° = 165°

∴ x = 165°/3 = 55°

Hence each base angle = 55°

and vertical angle = 55° + 15° = 70°

Step-by-step explanation:

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