Math, asked by laksmi72, 11 months ago

The vertical angle of an isosceles triangle is 72 degree. Find its base angles

Answers

Answered by priyasharma43
12

Answer:

72°+72°=144° .

180° - 144°=36° .

Then the Base angle is of 36°.

Answered by SocioMetricStar
2

The base angles of  isosceles triangle are 54°

Step-by-step explanation:

Let ABC is an isosceles triangle.

∠A is the vertical angle and ∠B and ∠C are base angles.

Let the value of base angles is x.

In an isosceles triangle, the base angles are equal.

Therefore, we have

∠A = 72°

∠B = ∠C = x

In a triangle, the sum of interior angles is 180°. Therefore, we have

∠A + ∠B + ∠C = 180°

72 + x + x = 180

2x = 180 - 72

2x = 108

x = 54

Therefore, the base angles of  isosceles triangle is 54°

#Learn More:

Vertical and base angles of isosceles triangle.

https://brainly.in/question/14785386

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