the vertical angle of an isosceles triangle is 80°. find measurement of its base angles.
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Answered by
17
50°
top angle = 80°
base angles are same so let them be x
x+x+80°=180°
2x =100°
x=50A
top angle = 80°
base angles are same so let them be x
x+x+80°=180°
2x =100°
x=50A
Answered by
7
in an isosceles , base angles are always equal——(1)
(2)——sum of 3 angles in a =180
.:if triangle name is ABC, & a, b, c are the resp. angles A(vert. angle), B, and C, then,
a+b+c=180 degree
=>80+b+c=180 [a=80 (as per ques.)]
=>2x=180-80=100 [b=c=x (let value of b and c be x)]
=>x=100/2=50
.:value of b and c (base angles) is:-
b=c=x=50 (ans.)
(2)——sum of 3 angles in a =180
.:if triangle name is ABC, & a, b, c are the resp. angles A(vert. angle), B, and C, then,
a+b+c=180 degree
=>80+b+c=180 [a=80 (as per ques.)]
=>2x=180-80=100 [b=c=x (let value of b and c be x)]
=>x=100/2=50
.:value of b and c (base angles) is:-
b=c=x=50 (ans.)
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