Question

The vertical angle of an isosceles triangle measures (2 p+18 degree ) and one of the base angle s measures 2 p find the value of all the angles of the triangle

Answer 1

answer:

let us suppose a triangle abc

let angle a be 2p+18°(given)

the base angles i.e angle b and angle c are equal

as it is given taht it is a isosceles triangle so two sides are equal and angle opposite to equal sides are equal..

so

angle b =angle c= 2p

now by angle sum property

angle a+b+c=180°

(2p+18)+2p+2p=180°

6p+18=180°

6p=180-18

p=162/6

p=27°

so,

angle a= 2×27+18= 72°

angle b=angle c= 2×27=54°