the vertical angle of and isoceles ∆ is 100° find its base
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Let its base angles be x.
In traingle Abc,
100°+x+x= 180° (Asp)
100°+ 2x= 180°
2x = 180°-100°
2x=80°
x =80°/2
x= 40°
therefore its base angles will be 40° each.
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In traingle Abc,
100°+x+x= 180° (Asp)
100°+ 2x= 180°
2x = 180°-100°
2x=80°
x =80°/2
x= 40°
therefore its base angles will be 40° each.
mark me as a brainliest
Answered by
0
The bases will be of 40° on each side.
Because in an isosceles triangle the angles opposite to equal sides are equal.
Let the equal angles be X.
Therefore, 100+2x=180
=2x= 180-100
=X= 80/2=40
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