Question

the vertical component of a vector is twice its horizontal component and exceeds the horizontal component 2 units. find the magnitude of the vector​

Answer 1

Answer:

this answer is 2√5

Explanation:

because the vertical component is 2×Horizontal

and horizontal is given 2

then Vertical component would be 4

and the theta will 90°

• so after solving with the formula R^2 =A^2 +B^2 + 2A×B×Cos(theta)

we got 2√5

Answer 2

Answer:

The magnitude of vector is

$2 \sqrt{5} \: units$

Explanation:

Let the vector be

$P = xi + yj$

Given that,the vertical component of the vector is twice the horizontal component.Therefore,

$y = 2x - - > (1)$

Also given,the vertical component exceeds horizontal component by 2 units.Therefore,

$y = x + 2 - - > (2)$

Solving equations (1) and (2),we get

$2x = x + 2 = > x = 2$

If x is known,then y is

$y = 2x = 2(2) = 4$

Therefore,the values of x and y are known.Hence the vector is

$P = 2i + 4j$

The magnitude of vector is

$|P| = \sqrt{2 {}^{2} + 4 {}^{2} } = 2 \sqrt{5} \: units$

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