Question

the vertical component of the vector having magnitude 24 and angle with y axis is 60 ​

Answer 1

Answer:

Explanation:

Given :

• Magnitude of vector $(\tt \vec{v})$ = 24 units
• Angle $(\theta)$ = 60°

To Find :

• The vertical component of the vector.

Solution :

Applying vertical component formula,

$\tt \green{ Vertical \: component = \vec{v} \times cos \theta}$

Where,

• $\tt\vec{v}$ = Magnitude of vector
• $\tt\theta$ = Angle

Now,

$\tt \longrightarrow \: Vertical \: component = 24 \times cos60 {}^{ \circ} \\ \\ \tt \longrightarrow \: Vertical \: component = \not{24} \times \dfrac{1}{ \not2} \\ \\ \tt \longrightarrow \red{Vertical \: component = 12 \: units}$

Hence :

The vertical component of the vector is 12 units.

Answer 2

$\huge\sf \underline {\pink{ Solution}}$

Applying vertical component formula,

$\sf{\color{orange}{ Vertical \: component = \vec{v} \times cos \theta}}$

Where,

• $\sf\vec{v}$ = Magnitude of vector

• $\sf\theta$ = Angle

Now,

$\begin{gathered}\sf \longrightarrow \: Vertical \: component = 24 \times cos60 {}^{ \circ} \\ \\ \sf \longrightarrow \: Vertical \: component = \not{24} \times \dfrac{1}{ \not2} \\ \\ \sf \longrightarrow \red{Vertical \: component = 12 \: units}\end{gathered}$

Therefore : The vertical component of the vector is 12 units.