Question

The vertical height of a tree is 18 m.The uppermost part of the tree is broken by wind 5 m above the ground.At what distance does the uppermost part of the tree touch the ground from the foot of the tree?​

Answer 1

Answer:

i dont understand the question

Answer 2

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Let A’CB be the tree before it broken at the point C and let the top A touches the ground at A after it broke. Then ΔABC is a right angled triangle, at B.

AB = 12 m and BC = 5 m

Using Pythagoras theorem,

In ΔABC

(AC)² = (AB)² + (BC)²

(AC)² = (12)² + (5)²

(AC)² = 144 + 25

(AC)² = √169

(AC)² = 169

AC=13 m

Hence, the total height of the tree(A′B)

=AC+CB=13+5=18m.

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