Question

The vertices of a AABC are A(2, -11), B(2, 13) and C(-12, 1).
Find the equations of its sides.​

Answer 1

Step-by-step explanation:

Equation b for AB..

y+11/x-2=13+11/2-2

x-2/y+11=0/25

for AC...

y-1/x+12=_13/14

for BC

y-13/x-12=12/25