Question

The vertices of a diagonal of a square are (4, 3) and (4, –3). Find the area?

Answer 1

Answer:

Step-by-step explanation:

Let us consider ( 4,3 ) be ( x1,y1 ) and (4 , -3 ) be ( x2 , y2 ).

Therefore, by distance formula , [x2 - x1 ] + [ y2 - y1 ]= (4-3)+(-3-3)

= 1+(-6)

= 1-6

= 5

Hence ,length of diagonal of a square is 5 units .

Hence,

Side of a square= 1/root2 x diadonal

= 1 / root 2 x 5

= 5 / root 2

This is the side of a square

Now , by using formula of area of a square , we can solve it.

Answer 2

Distance between given two points is sqrt[(4-4)^2 + (3- -3)^2]
= sqrt(36) =6

So diagonal = 6

Side = diagonal/sqrt(2)
=6/sqrt(2)

Area = side^2
= [6/sqrt(2)]^2
=36/2
= 18