Question

The vertices of a parallelogram are A(x1, y1), B(x2, y2), C(x3, y3), and D(x4, y4). Which of the following must be true if parallelogram ABCD is proven to be a rectangle?

Answer 1

Step-by-step explanation:

if ABCD must be a rectangle , then the distance of the opposite sides must be equal and the length ( distance ) of diagonals should be equal

so, in a parallelogram ABCD ,

= > AB = CD

√( x2 - x1) square + (y2 - y1 ) square. = √( x4- x3)

square + (y4 - y3 ) square ............ (1)

= > AD = BC

√ (x4- x1 ) square + ( y4- y1 ) square = √ ( x3 - x2 ) square + ( y3 - y2) square ...............(2)

also diagonals, AC = BD

√ ( x3 - x1 ) square + (y3-y1 ) square = √(x4 - x2) square +( y4 - y3 ) square ................. (3)

so using (1), (2) and (3) , it can be proven that ABCD is a rectangle

hope u understand

your answer depends on the options u have with the questions .

Answer 2

Answer:

the answer is 57

Step-by-step explanation: