Question

The vertices of a parallelogram taken in order are A(3, 4), B(9,5), C(7, 2x), and Dcy, 15). Find the value of xy.​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

If A(3,4), B(9,5), C(7,2X) and D(y,15) are the vertices of a parallelogram, then the diagonals intersect each other at a point.

So,

Mid-point of AC= Mid-point of BD.

Mid-point of a line joining (x1,y1) and (x2,y2):

p(x,y)=[x1+x2/2, y1+y2/2].

[3+7/2, 4+2x/2]=[9+y/2,5+15/2]

[10/2,4+2x/2]=[9+y/2, 20/2]

[5,4+2x/2]=[9+y/2,10]

By equating the equal coordinates:

5=9+y/2. 4+2x/2=10

10-9=y. 2x=20-4=16

1=y. x=16/2=8.

Step-by-step explanation:

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