the vertices of a right angle traingle PQR are P(8,0),Q(0,0) and R(0,-6) .show that the length of the hypotenuse is 10 units.
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L(PQ) =8 UNITS +ve x direction
L (QR) = 6 units - ve y direction
Use pythagoras theorem
(PQ)^2 + (QR) ^2 = (PR) ^2
8^2 + (-6)^2 = (PR) ^2
(PR) ^2 = 100
PR = sqrroot (100) = 10 units.
L (QR) = 6 units - ve y direction
Use pythagoras theorem
(PQ)^2 + (QR) ^2 = (PR) ^2
8^2 + (-6)^2 = (PR) ^2
(PR) ^2 = 100
PR = sqrroot (100) = 10 units.
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