Question

The vertices of a triangle ABC are A(2,1), B(8,3) and C(5, 6) and D is the mid-point of AB,
then prove that ∆ABC =2∆ADC.

can any one solve it step by step plzz no spamming step by step solution needed Chapter - Coordinate Geometry ​​

Answer 1

Step-by-step explanation:

ANSWER

Let A(2,1),B(−2,3),C(4,5) be vertices of △ABC and AD be the median.

D be mid point of BC.

D=(2−2+4,23+5)

⇒D=(1,4)

Now A(2,1)≡(x2,y2)andD(1,4)≡(x1,y1)

The equation of median AD is

y2−y1y−y1=x2−x1x−x1

⇒1−4y−4=2−1x−1

⇒−3y−4=1x−1

⇒−3x+3=y−4

⇒3x−3+