Question

the vertices of a triangle ABC are A(5,4) B(2,0) C(13,4). the bisector of angle meets BC in D. Find the coordinates of D.​

Answer 1

Answer:

$( \frac{15}{2} .2)$

Step-by-step explanation:

since D is the mid point of BC

since D is the mid point of BC therefore . by the mid point formula

$d(x.y) = (\frac{13 + 2}{2} ).( \frac{4 + 0}{2} )$

$x = \frac{15}{2} and \: y = 2$

CORDINATES OF D ARE ( 15/2 , 2 )