The vertices of a triangle ABC, right angled at B, are A(-2, 1), B(2,-2) and C(k, 2) Find the value of k.
walker15752:
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in triangle ABC
ABis perpendicular to BC
3/4×4/k-2=1
3=k-2
k=5
ABis perpendicular to BC
3/4×4/k-2=1
3=k-2
k=5
Answered by
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Heya!!!
Kindly refer to the attachment for solution..
Hope it helps ^_^
Kindly refer to the attachment for solution..
Hope it helps ^_^
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