The vertices of a triangle are (8,-10) (7,-3) (0,-4) prove angle abc is a right angle
Answers
Answered by
2
Step-by-step explanation:
If A(8,-10), B(7,-3), C(0-4)
AB= √(7−8)^2+(−3−−10)^2
=√50
AC=√(0−8)^2+(−4−−10)^2
=√100
BC=√(0−7)^2+(−4−−3)^2
=√50
If its a right triangle
Pythagoras Theorm
AC^2 = BC^2 + AC^2
100 = 50 + 50
100 = 100
Hence its a right triangle
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Answered by
0
Step-by-step explanation:
Let three points be A(8,-10),B(7,-3),C(0,-4).
AB=√(x2-x1)^2+(y2-y1)^2
=√(7-8)^2+(-3+10)^2
=√50
BC=√(0-7)^2+(-4+3)^2
√50
AC =√(0-8)^2+(-4+10)^2
=√100
If it is right angled triangle then using hypotenuse
AC^2=AB^2+BC^2
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