Math, asked by vijmoleramanggi, 1 year ago

the vertices of a triangle are A(0,0) B(3,√3) and C(0,2√3). find the perimeter of the triangle.

Answers

Answered by TaherK
0
let the base of the triangle be AC which is on the y axis therefore the length of the base is 2√3 units
the height of the triangle will be x coordinate of B which is 3

the area of a triangle is given by 1/2*b*h=1/2*2√3*3=3√3=5.196 sq. units
Answered by bhagathmanoj2905
0

Answer:

Step-by-step explanation:

let the base of the triangle be AC which is on the y axis therefore the length of the base is 2√3 units

the height of the triangle will be x coordinate of B which is 3

the area of a triangle is given by 1/2*b*h=1/2*2√3*3=3√3=5.196 sq. units

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