The vertices of a triangle are A(1,4,2),B(-2,1,2),C(2,3,-4) then angle theta is equal to
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ANSWER
DC
BD
=
AC
AB
AB=
3
2
+2
2
+1
2
=
14
AC=
1
2
+2
2
+3
2
=
14
D is mid point of BC
A(1,1,2), D(3,3,3)
AD
=2
i
+2
j
+
k
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