Question

the vertices of a triangle are A(-2,1), B(2,2) and C(6,-2). Find the equation of the altitude drawn from A on BC​

Answer 1

Answer:

Solution:-

Let ABC be the triangle with vertices A(2,−2),B(1,1) and C(−1,0)&AD be the altitude of △ABC drawn from A.

Let m1&m2 be the slope of line AD and BC respectively.

Now, AD⊥BC

∴m1×m2=−1

⇒m1=m2−1⟶(i)

Slope of line BC-

Slope of a line joining points (x1,y1)&(x2,y2)=x2−x1y2−y1

∴ Slope of BC joining B(1,1)&C(−1,0)=−1−10−1=−2−1=21

On substituting the value of m2 in eqn(i), we get

m1=Solution:-

Let ABC be the triangle with vertices A(2,−2),B(1,1) and C(−1,0)&AD be the altitude of △ABC drawn from A.

Let m1&m2 be the slope of line AD and BC respectively.

Now, AD⊥BC

∴m1×m2=−1

⇒m1=m2−1⟶(i)

Slope of line BC-

Slope of a line joining points (x1,y1)&(x2,y2)=x2−x1y2−y1

∴ Slope of BC joining B(1,1)&C(−1,0)=−1−10−1=−2−1=21

On substituting the value of m2 in eqn(i), we get

m1=-1(1/2)=-2