The vertices of a triangle are A(3,4), B(2,0)
and C(-1,6). Find the equations of the lines
containing
(a) side BC (b) the median AD
(c) the mid points of sides AB and BC.
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Answer:0 Step-by-step explanation:Vertices of AABC are A(3, 4), B(2, 0) and C(-1, 6).Let D and E be the midpoints of side AB and side BC respectively.=(³+2, 4+0) = ( ²1, 2). 5
:. D = andE = (²-¹, 0+ 6) = (1, 3) 2 1 2.
. the equation of the line
DE is A(3, 4)- 2 3-2 1 50/2 52y 2 2x 5
.: = 1 -4- 4(y-2) = 2x - 5- 4y + 8 = 2x - 52x + 4y - 13 = 0. i hope this will help you plz mark me brilliant
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