Question

the vertices of a triangle are A (-5,3), B (P, - 1), & C (6, q). find the value of p & q if the centroid of triangle ABC is the point (1, - 1)​

Answer 1

Answer:

P=2, q=-5

Step-by-step explanation:

Attached formula to calculate centroid for a triangle

I have calculated p

similarly calculate q

Answer 2

The value of p is 2 and value of the -5.

Step-by-step explanation:

The vertices of a triangle are A (-5,3), B (p, - 1), and C (6, q).

Centroid of a triangle:

$(\dfrac{x_1+x_2+x_3}{3},\dfrac{y_1+y_2+y_3}{3})$

By using formula, Centroid of triangle ABC is

$(\dfrac{-5+p+6}{3},\dfrac{3+(-1)+q}{3})$

$(\dfrac{p+1}{3},\dfrac{2+q}{3})$

It is given that the centroid of triangle ABC is the point (1, - 1)​.

$(\dfrac{p+1}{3},\dfrac{2+q}{3})=(1,-1)$

On comparing both sides we get

$\dfrac{p+1}{3}=1$

$p+1=3$

$p=3-1$

$p=2$

The value of p is 2.

$\dfrac{2+q}{3}=-1$

$2+q=-3$

$q=-3-2$

$q=-5$

Therefore, the value of q is -5.

#Learn more

Find centroid of triangle of abc a (3-1) b (10,7) and c (5,3).

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