.The vertices of a tringleABC are A (5,5), B(1,5)
and c(0,1) A line is drawn to intersect sides
AB and Ac at p and q respectively, such that
AP/AB = AC/AC = 3/4 find the length of the segment
pq.
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We have,ABAP=ACAQ=43
⇒AP+PBAP=AQ+QCAQ=43
⇒AP+PBAP=43,AQ+QCAQ=43
⇒4AP=3AP+3PBand4AQ=3AQ+3QC
⇒AP=3PBandAQ=3QC
⇒PBAP=13andQCAQ=13
⇒PandQdivideABandACrespectivelyinthesamerat
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