Question

The vertices of ∆ ABC are A(-2, 1), B(5, 4) and C(2, -3) respectively. Find the area of triangle and
height along the side AC.

Answer 1

Answer:

in triangle BOC and triangle COD

BO = CO (both are radius)

∠BDO=∠CDO =90°

BD is common in both triangle

so both triangle are similar

so ∠BOD=∠COD

as we know angle at the center is double of the angle of corcumferece

∠BOC=2∠BAC

⇒2∠BOD=2∠BAC (as we proved above)

⇒∠BOD=∠A

hence proved.