The vertices of ABC are A(2,3), B(-2,1) and C(-1,1)
(a) FInd the lengths of AB, BC and CA
(b) Show that ABC is a right angled triangle
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Step-by-step explanation:
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Answer
Let A(2,1),B(−2,3),C(4,5) be vertices of △ABC and AD be the median.
D be mid point of BC.
D=(
2
−2+4
,
2
3+5
)
⇒D=(1,4)
Now A(2,1)≡(x
2
,y
2
)andD(1,4)≡(x
1
,y
1
)
The equation of median AD is
y
2
−y
1
y−y
1
=
x
2
−x
1
x−x
1
⇒
1−4
y−4
=
2−1
x−1
⇒
−3
y−4
=
1
x−1
⇒−3x+3=y−4
⇒3x−3+y−4=0
⇒3x+y−7=0
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