Question

the vertices of right-angled triangle are A(1,0),B(7,0), and C(1,8).Plot the points A,B, and C on a sheet of graph paper.Hence,find the area of triangle ABC​

Answer 1

Answer:

Formula based question

√(x2-x1)²+(y2-y1)²

But u can write

√(x1-x2)²+(y1-y2) ²

GIVEN A=1,0 b=7,0

x1=1. y1=0

x2=7. y2=0

Triangle vertices

Ab,bc,ac

AB=√(1-7)²+(0-0)²

√6²+0²

AB = √36

BC = √(7-1)²+(0-8)²

√6²+8²

√36+64

√100

AC = √(1-1)²+(0-8)²

√8²

√64

NOW,

AB²+BC²=AC²

IN THIS CASE U HAVE TO PROVE SO MINOR CHANGES

AB²+AC²=BC²

36+64=100

100=100

MARK AS BRAINLIEST

Answer 2

Step-by-step explanation:

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