the vertices of right-angled triangle are A(1,0),B(7,0), and C(1,8).Plot the points A,B, and C on a sheet of graph paper.Hence,find the area of triangle ABC
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Answer:
Formula based question
√(x2-x1)²+(y2-y1)²
But u can write
√(x1-x2)²+(y1-y2) ²
GIVEN A=1,0 b=7,0
x1=1. y1=0
x2=7. y2=0
Triangle vertices
Ab,bc,ac
AB=√(1-7)²+(0-0)²
√6²+0²
AB = √36
BC = √(7-1)²+(0-8)²
√6²+8²
√36+64
√100
AC = √(1-1)²+(0-8)²
√8²
√64
NOW,
AB²+BC²=AC²
IN THIS CASE U HAVE TO PROVE SO MINOR CHANGES
AB²+AC²=BC²
36+64=100
100=100
MARK AS BRAINLIEST
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Step-by-step explanation:
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