The vertices of the triangle ABC are A(I,7), B(9-2) and c (3,3). Find the slope and equation of the median through A
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Median through A will divide CB into two equal parts, and the new point( say D ) will be the mid point of CB.
Using mid point formula:
Co. of D = ( {9+3}/2 , {-2+3}/2 )
Co. of D = ( 6, 1/2 )
Slope of AD -
= > { 7 - 1/2 } / { 1 - 6 }
= > ( 13/2 ) / (-5)
= > - 13/10
Hence, eq. is
= > ( y - 1/2 ) = (-13/10) ( x - 6 )
= > 10y - 5 = - 13x + 78
= > 13x + 10y - 83 = 0
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