Question

the vertices of the triangle are A(0,0) B(0,2) C(2,0) the distance between the circumcenter and the orthocenter is

Answer 1

Answer:

Step-by-step explanation:

Given A(0,0) B(0,2) C(2,0)

A = (0,0) this is the point at which angle is 90 degrees

And Circumcentre will be mid point of hypotenuse BC= (1,1)    

Thus required distance is = The distance between A and the midpoint of BC

$= \sqrt{1^{2}+1^{2} } \\\\= \sqrt{2}$

Hence, the distance between the circumcenter and the orthocenter = $\sqrt{2}$