Question

The vertices of triangle ABC are A(-1,3), B(1, 1) and C(5, 1). Find the length of the median to (i) AB,
(i) AC, (iii) BC.​

Answer 1

Answer:

Let AD be the median though A of ΔABC Then D is the mid-point of BC

Co-ordinates of D are (

2

1+5

,

2

−1+1

),i.e.(3,0)

∴AD=

(3+1)

2

+(0−3)

2

=

16+9

=

25

=5 units

solution

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