Question

The vertices of triangle ABC are A (2,0,0), B (0, 1.0), C (0, 0, 2). Its orthocenter is H and circumcentre is 'S'. 'P' is a point
equidistant from A, B, C and the origin 'O'. Then
Q. The area of Triangle ABC is
(A) 1.41
(B) 1.73
(C)1.41*1.73
(D)3

Answer 1

Answer:

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