Question

The vertices of triangle ABC are A(2,0) B(-1,7) and C(4,5). BX is the median of triangle ABC corresponding to side AC, if point P on BX divides BX in the ratio 2:5, then find the coordinates of point P.

Answer 1

hope this answer will be helpful ^_^

Answer 2

Given:  A(2,0) B(-1,7) and C(4,5),  

            BX is the median of triangle ABC,  

            P divides BX in the ratio 2:5

To find: Coordinates of point P

Solution:

• Since we know that X is the mid point of the side AC, as BX is the median.

• So, X = (2+4/2 , 0+5/2)

              X = (3, 5/2)

• Now, we know that   P divides BX in the ratio 2:5, so by using the formula:

              P = (mx2 + nx1)/ (m+n), (my2 + ny1)/ (m+n)

• Putting all the values in the formula, ewe get:

             P = (2)(3)+(5)(-1) / (2+3) , (2)(5/2) + (5)(7) / (2+3)

             P = 1/5 , 40/5

             P = (1/5, 8)

Answer:

• So the coordinates of P are :(1/5,8)