Question

The viscosity of water is 1 cp. Express the viscosity of water in (a) Pa. sec (b) stoke​

Answer 1

Viscosity of water

Water has a viscosity of 0.0091 poise at 25 °C, or 1 centipoise at 20 °C. As a function of temperature T (K): (Pa·s) = A × 10B/(T−C) where A=2.414 × 10−5 Pa·s ; B = 247.8 K ; and C = 140 K .

Answer 2

Viscosity of water $Pa - sec$ is 0.001 and in stroke is 0.01

Explanation:

• CGS unit of viscosity is centipoise ($cP$) which is equal to the 0.01 (P)Poise

• SI unit of viscosity is Pascal sec which is corresponding to the force applied per unit surface area divided by shear rate.

• 1 $cP$ (centipoise) equal to 1milli Pascal sec

• Viscosity is 1$cP$ (centipoise) equal to 1milli Pascal sec so to give its viscosity in $Pa - sec$ we need to divide the 1 $cP$ by 1000 so its answer is 0.001 $Pa - sec$

• CGS unit of kinetic viscosity is  centistokes ($cSt$), which is corresponding to 0.01 stokes ($St$). Viscosity 1 ($cSt$) equal to 0.01 stokes ($St$