Question

The vividh bharati station of all india radio delhi broadcast on a frequency of 1368 khz calculate the wavelength of the electromagnetic radio emitted by transmitter. Which part of the electromagnetic spectrum does 8 belong to

Answer 1

${\huge{\underline{\underline{\mathcal{\orange{♡ANSWER♡}}}}}}$

• ⭐The$\pink{\tt{Wavelength}}$ λ,is equal to $\red{\tt{c}}$/$\purple{\tt{v}}$.
• ⭐where $\green{\tt{c}}$ is the speed of $\red{\tt{electromagnetic radiations in vaccum}}$ and $\blue{\tt{v}}$is the $\purple{\tt{frequency substituting}}$ .
• ⭐The given values ,we have

• ⭐ λ = c/v
• ⭐$\frac{3.00×10^8ms^-1}{1368kHz}$

• ⭐$\frac{3.00×10^8ms^-1}{1368×10^3s/-1}$
• ${219.3m}$

Answer 2

Answer :

Given -

• c = 3.00 × 10⁸ m/s
• v = 1,368 kHz

To Find -

• λ = ?

Solution -

We know that, λ = c/v.

[λ = c/v,

λ = Wavelength,

c = Speed of Electromagnetic wave in vaccuum,

v = frequency]

➸ λ = 3.00 × 10⁸/1368

➸ λ = 3.00 × 10⁸/1368 × 10³

➸ λ = 219.3 m

Hence, wavelength = 219.3 m.

And it belongs to radiowaves.