Question

The Vividh Bharati station of All India
Radio, Delhi broadcasts on a frequency
of 1,368 kHz (kilo hertz). Calculate the
wavelength of the electromagnetic
radiation emitted by transmitter. Which
part of the electromagnetic spectrum
does it belong to?​

Answer 1

Answer:

Explanation:

v=nλ

n= 1368 * 10^3 Hz

λ=  3*10^8/ 1368 * 10^3

= 219.2 m

= 0.2 *10^-3 m

they belong to infrared rays

Answer 2

Formula Used :

$\displaystyle \qquad \: \: \: \: \: \bfλ = \frac{c}{υ}$

Where,

• λ = Wavelength
• c = Speed of electromagnetic radiation in vacuum
• υ = Frequency

Substituting the given values, we have

$\displaystyle \qquad \: \: \: \: \: \sfλ = \frac{c}{υ}$

$\displaystyle \qquad \qquad \sf= \frac{3.00×10^8ms^{-1}}{1368 \: kHz}$

$\displaystyle \qquad \qquad \sf= \frac{3.00×10^8ms^{-1}}{1368 \times {10}^{3} {s}^{ - 1} }$

$\displaystyle \qquad \qquad \bf= 219.3 \: m$

This is a characteristic radiowave wavelength.

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