Question

the vol of 1 kg of oxygen gas at Ntp is 0.7 m cube. Specific heat of oxygen at constant volume is 653j/kg k the Specific heat of oxygen at constant pressure in J/kg k is​

Answer 1

Explanation:

We know that N.T.P condition as follows

P=1.01×10

5

N/m

2

,T=25

0

, C=298K

Applying gas equation

PV=mRT

plugging the values in the above equation

1.01×10

5

×11.2=1×R×298

R=3795.97J/kg/K

Now according to the Mayer's law

C

P

−C

V

=R

plugging the values in the above equation

C

P

−10046=3795.97

C

P

=13841.97J/kg/K