The voltage across the load is to be maintained at 12 V as load current varies from 0 to 200 mA. Design the regulator
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The voltage across the load is to be maintained at 12 V as load current varies from 0 to 200 mA. Design the regulator
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Answer:
The voltage that is across the load current that varies from 0 to 200mA is 2.5 W.
Explanation:
- A voltage is defined as the expression of the quantitative of any potential differences between the charges of two points present in the electrical field is called as electromotive force.
The mathematical formula of the voltage:
V = IR
Here,
V is voltages
I is the current
R is resistances measured in ohms
Given that:
voltage across the load = 12 V
load current varies = 0 to 200 mA
To find:
the value and design of the regulator =?
Solution:
The maximum current through the diode is 200mA.
The voltage that will begin to drop across the diode and the load is same because they are connected in parallel.
Therefore, the maximum power dissipated in the diode will be 200mA times 12V = 2.5W
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