Physics, asked by amisha9466, 11 months ago

The voltage and current in a series AC circuit are given by V = V0cos ωt and i = i0 sin ωt. What is the power dissipated in the circuit?

Answers

Answered by azizalasha

0

Answer:

solved

Explanation:

power dissipated = vi = V0i0sin ωtcos ωt = 2V0i0sin ωtcos ωt /2

= V0i0sin 2ωt /2

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