Physics, asked by anwarkhanmcc442, 3 months ago

The voltage drop of 10V develops across a 1Kohm resistor. The power dissipated in the resistor is?​

Answers

Answered by binitlenka06
5

Answer:

Power dissipated would be equal to 0.1 Watt.

Explanation:

P = V^2 / R

P = 10^2 / 1000

P = 100/1000

P = 0.1 Watt

BHAI PLEASE, PLEASE MARK THIS ANSWER AS BRAINLIEST.

Similar questions