Question

The voltage of an AC source varies with time according to the relation E = 100 sin(50xt) cos(50xt) V. Select the correct statement (1) Peak voltage of source is 50 V (2) Frequency of source is 100 Hz (3) Frequency of source is 50 Hz (4) Both (1) and (3)​

Answer 1

Answer:

yes

Explanation:

Peak voltage is when sin function and cos function both are maximum which is

2

1

So, peak voltage = 50×

2

1

×

2

1

=

2

50

=25V.

V=50sin100πtcos100πt

=25sin200πt (∵2sinACosA=sin2A)

So, frequency is

2π

200π

=100Hz