CBSE BOARD X, asked by ridasaifi06, 1 month ago

the voltage of the hair dryer is 190 V and electric current is 19a . What is its power?

Answers

Answered by keyapara

1

Answer:3.61 kW

Explanation:

given:- V=190V

I=19A

P=?

we know what P=VI

therefore, P=190*19

P=3610W

P=3.61 kW

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