Question

The voltage u(t) at a capacitor changes with time t during the charging process as follows
u(t) = 100 V(1 – e-t/T) with 7205
(T> 0: unknown time constant)
4.1 Determine the time constant (tau) with help of the measurement value u(t=2s) = 80 V.
1P 1.24
OPO 2.24
4.2 After which time does the voltage reach 50 V?
OP 0.66 s
OPI 0.76 s
OPD 0.96 s
1P7 0.86 s
4.3 Calculate the voltage at t = 5 s
OPD 95.2 V
1P7 98.2 V
I
OPO 96.2 V
OPO 97.2 V​

Answer 1

Answer:

answer is 2

Step-by-step explanation:

we know that

s=ut+1/2at^2

s=vt-1/2at^2

add this

2s=(v+u)t