The voltmeter shown in the figure is18v across 50 ohm
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Answered by
0
I guess u r asking current if so then there is the answer
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arpit0522as:
No the resistance of the voltmeter
Answered by
2
let the R of voltmeter be x,now 50 ohm,are in parellel
hence net Resistance;50x/50+x=y..............(1)
now current in the circuit i=net emf/net resistance
i=30/24+y..................(2)
now
v=i*Rnet
18=30/24+y*y
then
y=36 (when u will solve)
now putting value in equ.(1)
y=50x/50+x
18=25x/50+x
then
x=900/7=128.57 oh
hope this will be help u
if u like please mark as brainlist...
hence net Resistance;50x/50+x=y..............(1)
now current in the circuit i=net emf/net resistance
i=30/24+y..................(2)
now
v=i*Rnet
18=30/24+y*y
then
y=36 (when u will solve)
now putting value in equ.(1)
y=50x/50+x
18=25x/50+x
then
x=900/7=128.57 oh
hope this will be help u
if u like please mark as brainlist...
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