the volume in cm^3 of 3.01×10^23 molecules of O2 gas at S.T.P ?
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We know that one mole of a gas at Standard temperature and pressure (STP) take the volume =22.4 L
And one mole of a gas contain=6.02* 10^23 molecules.
so the 6.02 *10^23 molecule will takes up the volume =22.4 L
Also the 1 molecule will takes up the the volume = 22.4 / 6.02*10^23
Hence the 3.01 *10^23 will takes up the volume =(22.4/6.02*10^23 ) * 3.01*10^23 = 11.2 liter
Thus the 3,01*10^23 of oxygen will have the volume of 11.2 liter.
in order to convert the liter in to cm^3 = 11.2*1000 = 11200 cm³
11200cm³ will be the volume of oxygen
And one mole of a gas contain=6.02* 10^23 molecules.
so the 6.02 *10^23 molecule will takes up the volume =22.4 L
Also the 1 molecule will takes up the the volume = 22.4 / 6.02*10^23
Hence the 3.01 *10^23 will takes up the volume =(22.4/6.02*10^23 ) * 3.01*10^23 = 11.2 liter
Thus the 3,01*10^23 of oxygen will have the volume of 11.2 liter.
in order to convert the liter in to cm^3 = 11.2*1000 = 11200 cm³
11200cm³ will be the volume of oxygen
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